Advertisements
Advertisements
प्रश्न
Divide: 63a4b5c6 by −9a2b4c3
योग
उत्तर
`(63"a"^4"b"^5"c"^6)/(-9"a"^2"b"^4"c"^3)=(63/(-9))("a"^4/"a"^2)("b"^5/"b"^4)("c"^6/"c"^3)`
= −7a4−2 . b5−4 . c6−3
= −7a2bc3
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Carry out the following divisions:
34x3y3z3 ÷ 51xy2z3
Divide: 24x3y3 by −8y2
Do the following division.
7x2y2z2 ÷ 14xyz
`(42"a"^4"b"^5(_))/(6"a"^4"b"^2)` = `(_)"b"^((_))"c"^2`
Divide x3y2 by x2y
Simplify `(3"m"^2)/"m" + (2"m"^4)/("m"^3)`
Divide: (4m2n3 + 16m4n2 – mn) by 2mn
Divide:
5xy2 – 18x2y3 + 6xy by 6xy
Find the simple interest on Rs. 5a2b2 for 4ab years at 7b% per annum
The cost of a notebook is Rs. 10ab. If Babu has Rs. (5a2b + 20ab2 + 40ab). Then how many notebooks can he buy?
