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प्रश्न
Divide: 63a4b5c6 by −9a2b4c3
बेरीज
उत्तर
`(63"a"^4"b"^5"c"^6)/(-9"a"^2"b"^4"c"^3)=(63/(-9))("a"^4/"a"^2)("b"^5/"b"^4)("c"^6/"c"^3)`
= −7a4−2 . b5−4 . c6−3
= −7a2bc3
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