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प्रश्न
Divide a rope of length 560 cm into 2 parts such that twice the length of the smaller part is equal to `1/3` of the larger part. Then find the length of the larger part.
उत्तर
Let the length of the smaller part of the rope be ‘x’ cm and that of the larger part be ‘y’ cm.
According to the first condition,
The total length of the rope is 560 cm.
∴ x + y = 560 ...(i)
Twice the length of the smaller part = 2x
`1/3` rd length of the larger part = `1/3`y
According to the second condition,
2x = `1/3`y
∴ 2x × 3 = y
∴ 6x – y = 0 ...(ii)
Adding equations (i) and (ii),
x + y = 560
6x − y = 0
+__________
7x = 560
x = `560/7`
∴ x = 80
Substituting x = 80 in equation (ii),
6x – y = 0
∴ 6(80) – y = 0
∴ 480 – y = 0
∴ y = 480
∴ The length of the larger part of the rope is 480 cm.
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