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प्रश्न
Divide. Write the quotient and the remainder.
(6x5 − 4x4 + 8x3 + 2x2) ÷ 2x2
उत्तर
(6x5 − 4x4 + 8x3 + 2x2) ÷ 2x2
= \[\frac{6 x^5 - 4 x^4 + 8 x^3 + 2 x^2}{2 x^2}\]
= \[\frac{2 x^2 \left( 3 x^3 - 2 x^2 + 4x + 1 \right)}{2 x^2}\]
= \[3 x^3 - 2 x^2 + 4x + 1\]
So, quotient = \[3 x^3 - 2 x^2 + 4x + 1\] and remainder = 0
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