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Divide. Write the quotient and the remainder. (21x4 − 14x2 + 7x) ÷ 7x3 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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प्रश्न

Divide. Write the quotient and the remainder.

(21x4 − 14x2 + 7x) ÷ 7x3

योग

उत्तर

(21x4 − 14x2 + 7x) ÷ 7x3

= \[\frac{21 x^4 - 14 x^2 + 7x}{7 x^3}\] 

= \[\frac{7 x^3 \times 3x - 14 x^2 + 7x}{7 x^3}\] 

= \[\frac{7 x^3 \times 3x}{7 x^3} + \frac{- 14 x^2 + 7x}{7 x^3}\] 

= \[3x + \frac{- 14 x^2 + 7x}{7 x^3}\]

So, quotient = 3x and remainder = -14x2 + 7x

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Division of Polynomials - Practice Set 10.1 [पृष्ठ ६४]

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बालभारती Mathematics [English] 8 Standard Maharashtra State Board
अध्याय 10 Division of Polynomials
Practice Set 10.1 | Q 8 | पृष्ठ ६४
बालभारती Integrated 8 Standard Part 3 [English Medium] Maharashtra State Board
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Practice Set 10.1 | Q 1. (8) | पृष्ठ ३९
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