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Question
Divide. Write the quotient and the remainder.
(21x4 − 14x2 + 7x) ÷ 7x3
Solution
(21x4 − 14x2 + 7x) ÷ 7x3
= \[\frac{21 x^4 - 14 x^2 + 7x}{7 x^3}\]
= \[\frac{7 x^3 \times 3x - 14 x^2 + 7x}{7 x^3}\]
= \[\frac{7 x^3 \times 3x}{7 x^3} + \frac{- 14 x^2 + 7x}{7 x^3}\]
= \[3x + \frac{- 14 x^2 + 7x}{7 x^3}\]
So, quotient = 3x and remainder = -14x2 + 7x
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