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Question
Divide. Write the quotient and the remainder.
(2y3 + 4y2 + 3) ÷ 2y2
Solution
(2y3 + 4y2 + 3) ÷ 2y2
= \[\frac{2 y^3 + 4 y^2 + 3}{2 y^2}\]
= \[\frac{2 y^2 \left( y + 2 \right) + 3}{2 y^2}\]
= \[\frac{2 y^2 \left( y + 2 \right)}{2 y^2} + \frac{3}{2 y^2}\]
= \[\left( y + 2 \right) + \frac{3}{2 y^2}\]
So, quotient = \[\left(y + 2 \right)\] and remainder = 3
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