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Maharashtra State BoardSSC (English Medium) 8th Standard

Divide. Write the quotient and the remainder. (8p3 − 4p2) ÷ 2p2 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Divide. Write the quotient and the remainder.

(8p3 − 4p2) ÷ 2p2

Sum

Solution

(8p3 − 4p2) ÷ 2p2

= \[\frac{8 p^3 - 4 p^2}{2 p^2}\] 

= \[\frac{2 p^2 \left(4p - 2 \right)}{2 p^2}\] 

= 4p - 2

So, quotient = 4p - 2 and remainder = 0

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Chapter 10: Division of Polynomials - Practice Set 10.1 [Page 64]

APPEARS IN

Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 10 Division of Polynomials
Practice Set 10.1 | Q 6 | Page 64
Balbharati Integrated 8 Standard Part 3 [English Medium] Maharashtra State Board
Chapter 3.1 Division of Polynomials
Practice Set 10.1 | Q 1. (6) | Page 39
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