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प्रश्न
Domain of the function defined by `f(x) = 1/sqrt(sin^2 - x) log_10 (cos^-1 x)` is:-
विकल्प
[0, 1]
(0, 1]
[0, 1)
(0, 1)
MCQ
उत्तर
(0, 1)
Explanation:
`sin^-1 x > 0` and `cos^-1 x > 0`
Now, `0 < sin^-1 x ≤ pi/2`
⇒ `0 < x ≤ 1` ......(i) and `0 < cos^-1 x ≤ pi`
⇒ `- 1 ≤ x < 1` ......(ii)
Combining (i) and (ii)
0 < x < 1
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