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प्रश्न
Draw a formula for the first five members of the homologous series beginning with the given compound.
H–COOH
उत्तर
The first five members of the homologous series beginning with the given compound are
H–COOH : Methanoic acid
CH3–COOH : Ethanoic acid
CH3–CH2–COOH : Propanoic acid
CH3–CH2–CH2–COOH : Butanoic acid
CH3–CH2–CH2–CH2–COOH : Pentanoic acid
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संबंधित प्रश्न
Draw a formula for the first five members of the homologous series beginning with the given compound.
H–CH=CH2
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
\phantom{}|\phantom{....}|\phantom{................}\\
\phantom{.}\ce{CH3\phantom{.}CH3}\phantom{..............}
\end{array}\]
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\[\ce{CH3 -CH2 -\overset{⊕}{C}H -CH2 -CH3}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
|\phantom{....................}\\
\ce{CH3 - C - CH - CH2 - CH2 - CH3}\\
|\phantom{....}|\phantom{................}\\
\ce{CH3}\phantom{..}\ce{CH3}\phantom{..............}\\
\end{array}\]
