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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ८

Draw a histogram for the given frequency distribution Age 41 − 45 46 − 50 51 − 55 56 − 60 61 − 65 66 − 70 71 − 75 Frequency 4 9 17 25 15 8 2 - Mathematics

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प्रश्न

Draw a histogram for the given frequency distribution

Age 41 − 45 46 − 50 51 − 55 56 − 60 61 − 65 66 − 70 71 − 75
Frequency 4 9 17 25 15 8 2
आलेख
योग

उत्तर

The given distribution is discontinuous.

Lower boundary = lower limit – `1/2` (gap between the adjacent class interval)

= `41 - 1/2` (1) = 40.5

Upper boundary = Upper limit + `1/2` (gap between the adjacent class interval)

= `45 + 1/2` (1) = 45.5

Now continuous frequency table is as below

Age 40.5 −  45.5 45.5 − 50.5 50.5 − 55.5 55.5 − 60.5 60.5 − 65.5 65.5 − 70.5 70.5 − 75.5
Frequency 4 9 17 25 15 8 2

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अध्याय 6: Statistics - Exercise 6.3 [पृष्ठ २३०]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
अध्याय 6 Statistics
Exercise 6.3 | Q 3 | पृष्ठ २३०

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