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प्रश्न
Draw an equilateral triangle with side 6.5 cm.
उत्तर
Steps of construction:
- Draw a line BC = 6.5 cm.
- With B as a centre and 6.5 cm as radius, draw an arc above the line BC.
- With C as a centre and 6.5 cm as radius, draw an arc cutting the previous drawn arc. Name the point of intersection as point A.
- Join AB and AC.
△ABC is the required equilateral triangle.
संबंधित प्रश्न
Construct a triangle of the measures given below.
In ∆SAT, l(AT) = 6.4 cm, m ∠A = 45°, m ∠T = 105°
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Construct ∆XYZ such that l(XY) = 3.7 cm, l(YZ) = 7.7 cm, l(XZ) = 6.3 cm.
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
Construct a triangle using the given data: PQ = 6.2cm, ∠P = 105° and ∠ = 45°
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct a triangle using the following data: PQ + PR = 10.6 cm, QR = 4.8 cm and ∠R = 45°
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
