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प्रश्न
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
उत्तर
In ΔABC,
AB = AC ....(given)
⇒ ∠ACB = ∠ABC = 75°
Steps:
1. Draw BC = 6cm.
2. Construct angle ∠BCM = 75° and ∠CBN = 75°
3. Ray CM and ray BN meets at A.
Thus, ABC is required angle.
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संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
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Construct a triangle of the measures given below.
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Construct a triangle using the given data: PQ = 4.8cm, QR = 6.3cm and PR = 5.5cm
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