Advertisements
Advertisements
प्रश्न
Draw ∠ ARP= 115° and bisect it.
उत्तर
APPEARS IN
संबंधित प्रश्न
Draw `angle ABC` of measure 80° and bisect it
Draw ∠ABC of measures 135°and bisect it.
Ponit M is the mid point of seg AB and AB = 14 then AM = ?
Observe the adjoining figure and write down one pair of interior angles.
Write down the equation of X- axis.
Draw seg AB of length 5.7 cm and bisect it.
Prove that “That ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides.”
Construct ∠ABC = 60° and bisect it
Construct ∠PQR = 115° and divide it into two equal parts
Draw Seg AB of length 9.7 cm. Take point P on it such that AP = 3.5 cm and A–P–B. Construct perpendicular to seg AB from point P.
Draw seg AB of length 4.5 cm and draw its perpendicular bisector
Point P is at a distance of 6 cm from line AB. Draw a circle of radius 4 cm passing through point P so that line AB is the tangent to the circle
