Advertisements
Advertisements
प्रश्न
Draw a ray diagram showing the image formation by a compound microscope. Hence obtained expression for total magnification when the image is formed at infinity.
उत्तर
A compound microscope consists of two convex lenses co-axially separated by some distance. The lens nearer to the object is called the objective. The lens through which the final image is viewed is called the eyepiece.
Magnifying power, when final image is at infinity:
The magnification produced by the compound microscope is the product of the magnifications produced by the eyepiece and objective.
`∴M = M_e xx M_0 ...... (1)`
Where, Me and M0 are the magnifying powers of the eyepiece and objective respectively.
If u0 is the distance of the object from the objective and v0 is the distance of the image from the objective, then the magnifying power of the
objective is `M_0 = (h')/h =L/f_0 ( using tanβ = (h/f_0) = =(h/L))`
Where, h, h' are object and image heights respectively and f0 is the focal length of the objective.
L is the tube length i.e. the distance between the second focal point of the objective and the first focal point of the eyepiece.
When the final image is at infinity, `M_e = D/f_e`
Magnifying power of compound microscope,`M = M_0 xx M_e = L/f_0 xx D/f_e`
APPEARS IN
संबंधित प्रश्न
Why must both the objective and the eyepiece of a compound microscope have short focal lengths?
When are two objects just resolved? Explain.
Draw a ray diagram to show the working of a compound microscope. Deduce an expression for the total magnification when the final image is formed at the near point.
In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. If the eye piece has a focal length of 5 cm and the final image is formed at the near point, estimate the magnifying power of the microscope.
Can the image formed by a simple microscope be projected on a screen without using any additional lens or mirror?
compound microscope consists of two convex lenses of focal length 2 cm and 5 cm. When an object is kept at a distance of 2.1 cm from the objective, a virtual and magnified image is fonned 25 cm from the eye piece. Calculate the magnifying power of the microscope.
Define the magnifying power of a microscope in terms of visual angle.
How does the resolving power of a microscope change when
(i) the diameter of the objective lens is decreased?
(ii) the wavelength of the incident light is increased ?
Justify your answer in each case.
The near vision of an average person is 25 cm. To view an object with an angular magnification of 10, what should be the power of the microscope?
The focal lengths of the objective and the eye-piece of a compound microscope are 1.0 cm and 2.5 cm respectively. Find the tube length of the microscope for obtaining a magnification of 300.
What is meant by a microscope in normal use?