Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = - 2x
उत्तर
First prepare a table as follows:
x | - 1 | 0 | 1 |
y | 2 | 0 | - 2 |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
y = 3x
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: 2x + 3y = 12
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.