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प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
उत्तर
To draw the graph of 2x - 3y = 6 and `x/(2) + y/(3) = 1` follows the steps:
First prepare a table as below:
X | -1 | 0 | 1 |
Y = `(2)/(3) xx 2` | `-(8)/(3)` | -2 | `-(4)/(3)` |
Y = `-(3)/(2) xx + 3` | `(9)/(2)` | 3 | `(3)/(2)` |
Now sketch the graph as shown:
From the graph it can verify that the lines are perpendicular.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
x + 3 = 0
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
y = 3x
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
Draw a graph of each of the following equations: 3x - 2y = 6
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.