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प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
उत्तर
To draw the graph of y = 3x - 1 and y = 3x + 2 follows the steps:
First, prepare a table as below:
| X | - 1 | 0 | 1 |
| Y = 3x -1 | - 4 | - 1 | 2 |
| Y = 3x + 2 | - 1 | 2 | 5 |
Now sketch the graph as shown
:
From the graph it can verify that the lines are parallel.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the linear equation given below:
x + 2y = 0
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph of the equation 3x - 4y = 12.
Use the graph drawn to find:
(i) y1, the value of y, when x = 4.
(ii) y2, the value of y, when x = 0.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: x + y - 3 = 0
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
