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प्रश्न
Draw the structural formula for the following compound:
isomer of n-butane
उत्तर
\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
\end{array}\]
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\[\begin{array}{cc}
\ce{H\phantom{...}H\phantom{...}H\phantom{..}}\\
|\phantom{....}|\phantom{....}|\phantom{..}\\
\ce{H - C - C - C - OH}\\
|\phantom{....}|\phantom{....}|\phantom{..}\\
\ce{H\phantom{...}H\phantom{...}H\phantom{..}}
\end{array}\]
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