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प्रश्न
Draw triangle with the measures given below.
In ∆PRS, l(RS) = 5.5 cm, l(RP) = 4.2 cm, m ∠R = 90°
उत्तर
Steps of construction:
- Draw a line RS = 5.5 cm.
- With R as a centre, draw an angle of 90°° and name it as ∠XRS.
- With R as a centre and 4.2 cm radius in compass, cut an arc on XR and name it P. Join PS.
∆PRS is the required triangle.
संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
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Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
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