Advertisements
Advertisements
प्रश्न
Draw triangle with the measures given below.
In ∆PRS, l(RS) = 5.5 cm, l(RP) = 4.2 cm, m ∠R = 90°
उत्तर
Steps of construction:
- Draw a line RS = 5.5 cm.
- With R as a centre, draw an angle of 90°° and name it as ∠XRS.
- With R as a centre and 4.2 cm radius in compass, cut an arc on XR and name it P. Join PS.
∆PRS is the required triangle.
संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Construct ∆XYZ such that l(XY) = 3.7 cm, l(YZ) = 7.7 cm, l(XZ) = 6.3 cm.
Construct a triangle using the given data: DE = 6.5cm, EF = 5.8cm and DF = 4.2cm
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct a triangle using the given data: XY - XZ = 1.5 cm, YZ = 3.4 cm and ∠X = 45°
Construct a triangle using the given data: Perimeter of triangle is 6.4 cm, and the base angles are 60° and 45°
