Question

`int_(-1)^1 log ((2 - x)/(2 + x)) "dx" = ?`

विकल्प

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Answer 1

0

Explanation:

Let f(x) = `log ((2 - x)/(2 + x))`

∴ f(- x) = `log ((2 - x)/(2 + x))^(-1)`

= -`log ((2 - x)/(2 + x))` = - f(x)

∴ f(x) is an odd function.

∴ `int_(-1)^1 log ((2 - x)/(2 + x))` dx = 0