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Question
`int_(-1)^1 log ((2 - x)/(2 + x)) "dx" = ?`
Options
0
1
- 1
2
MCQ
Solution
0
Explanation:
Let f(x) = `log ((2 - x)/(2 + x))`
∴ f(- x) = `log ((2 - x)/(2 + x))^(-1)`
= -`log ((2 - x)/(2 + x))` = - f(x)
∴ f(x) is an odd function.
∴ `int_(-1)^1 log ((2 - x)/(2 + x))` dx = 0
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