Advertisements
Advertisements
प्रश्न
Evaluate: (3−1 + 4−2 + 5−3)0
योग
उत्तर
(3−1 + 4−2 + 5−3)0 = 1 ...[∵ a0 = 1 where a ≠ 0]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Numbers - Exercise 1.6 [पृष्ठ ४५]
APPEARS IN
संबंधित प्रश्न
`(-1)^("even integer")` is _____________
For a ≠ 0, a0 is ______________
`(-1/3)^(-5)` = ____________
Evaluate: (50 + 6−1) × 33
Evaluate: (2−1 + 3−1) ÷ 6−1
Simplify: (32)3 × (2 × 35)−2 × (18)2
Simplify: `(9^2 xx 7^3 xx 2^5)/(84^3)`
Order the following from the least to the greatest: 1625, 8100, 3500, 4400, 2600
Find the value of:
`(–7)^(2 xx 7 - 6 - 8)`
Find the value of:
(80 – 20) × (80 + 20)
