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Evaluate the following limits: limx→0[6+x+x2-6x] - Mathematics and Statistics

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प्रश्न

Evaluate the following limits: `lim_(x -> 0) [(sqrt(6 + x + x^2) - sqrt(6))/x]`

योग

उत्तर

`lim_(x -> 0) [(sqrt(6 + x + x^2) - sqrt(6))/x]`

= `lim_(x -> 0) [(sqrt(6 + x + x^2) - sqrt(6))/x xx (sqrt(6 + x + x^2) + sqrt(6))/(sqrt(6 + x + x^2) + sqrt(6))]`

= `lim_(x -> 0) ((6 + x + x^2) - 6)/(x(sqrt(6 + x + x^2) + sqrt(6))`

= `lim_(x -> 0)(x + x^2)/(x(sqrt(6 + x + x^2) + sqrt(6))`

= `lim_(x -> 0) (x (1 + x))/(x(sqrt(6 + x + x^2) + sqrt(6))`

= `lim_(x -> 0) (1 + x)/(sqrt(6 + x + x^2) + sqrt(6)`   ...[∵ x → 0, ∴ x ≠ 0]

= `((1 + 0))/(sqrt(6) + sqrt(6)`

= `1/(2sqrt(6))`

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अध्याय 7: Limits - EXERCISE 7.3 [पृष्ठ १०३]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] 11 Standard Maharashtra State Board
अध्याय 7 Limits
EXERCISE 7.3 | Q I. 1. | पृष्ठ १०३

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