Advertisements
Advertisements
प्रश्न
Explain how you will determine experimentally the position of the centre of gravity for a triangular lamina (or a triangular piece of cardboard).
उत्तर
Take a triangular lamina. Make three fine holes at a, b, and c near the edge of the triangular lamina. Now suspend the given lamina along with a plumb line from hole 'a'. Check that the lamina is free to oscillate about the point of suspension. When the lamina has come to rest, draw a straight line ad along the plumb line. Repeat the experiment by suspending the lamina through hole 'b' and then through hole 'c' for which we get straight lines to be and cf, respectively. It is noticed that the lines ad, be and cf intersect each other at a common point G, which is the position of the centre of gravity of the triangular lamina, i.e., the point of intersection of medians.
APPEARS IN
संबंधित प्रश्न
The distance between two bodies is doubled. How is the magnitude of the gravitational force between them affected?
Following Fig shows piece of cardboard of uniform thickness cut into different shapes. Draw two lines to indicate the position of centre of gravity G.
Following Fig shows piece of cardboard of uniform thickness cut into different shapes. Draw two lines to indicate the position of centre of gravity G.
Fig. shows the dimensions of an acute angled triangle. By geometrical construction mark the C.G. of the triangle.
Give scientific reason for the following:
It is easier to push a boy standing on one leg than on both legs.
The centre of gravity of a hollow cone of height h is at distance x from its vertex where the value of x is ______.
What is Gravitational force? Give gravitational units of force.
Explain the term ‘centre of gravity’ of a body.
State two methods of increasing the stability of the body.
Mention the real-life applications of the center of gravity.