Advertisements
Advertisements
प्रश्न
Explain the following reaction.
Hydrated alumina is treated with aqueous NaOH solution.
उत्तर
When hydrated alumina is added to sodium hydroxide, the former dissolves in the latter because of the formation of sodium meta-aluminate.
\[\ce{Al_2O_3 . 2H_2O + 2NaOH -> 2 NaAlO_2+ 3H_2O}\]
APPEARS IN
संबंधित प्रश्न
Is boric acid a protic acid? Explain.
Explain what happens when boric acid is heated.
Write a balanced equation for NaH + B2H6 → ?
Write a balanced equation for \[\ce{H3BO3 ->[\Delta]}\]?
Boric acid is polymeric due to ______.
An aqueous solution of borax is _______.
Boric acid is an acid because its molecule ______.
Draw the structures of BCl3.NH3 and AlCl3 (dimer).
Explain the nature of boric acid as a Lewis acid in water.
When aqueous solution of borax is acidified with hydrochloric acid, a white crystalline solid is formed which is soapy to touch. Is this solid acidic or basic in nature? Explain.
A compound (A) of boron reacts with NMe3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved.
Aqueous solution of which of the following boron compounds will be strongly basic in nature?
Boron reacts with nitric acid to form ______.
Which one of the following methods is used to prepare borax crystals?
Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of “X” with 6-equivalents of “Y”. “X” and “Y”, respectively are ______.
The reaction of H3N3B3Cl3(A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H3N3B3(Me)3. Compounds (B) and (C) respectively, are ______.
