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Explain the variation of g with altitude. - Physics

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प्रश्न

Explain the variation of g with altitude.

संक्षेप में उत्तर

उत्तर

Consider an object of mass m at a height h from the surface of the Earth. Acceleration experienced by the object due to Earth is

g’ = `("GM")/(("R"_"e" + "h")^2)`

Mass at a height h from the center of the Earth

g’ = `("GM")/("R"_"e"^2 (1 + "h"/"R"_"e")^2)`

g’ = `("GM")/("R"_"e"^2) (1 + "h"/"R"_"e")^-2`

If h << Re

We can use Binomial expansion. Taking the terms up to first order

g’ = `("GM")/("R"_"e"^2) (1 - 2"h"/"R"_"e")`

g’ = `"g" (1 - 2"h"/"R"_"e")`

We find that g’ < g. This means that as altitude h increases the acceleration due to gravity g decreases.

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अध्याय 6: Gravitation - Evaluation [पृष्ठ ४४]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Gravitation
Evaluation | Q III. 9. | पृष्ठ ४४
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