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Express the Following in Terms of Log 2 and Log 3: Log128 - Mathematics

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प्रश्न

Express the following in terms of log 2 and log 3: log128 

योग

उत्तर

log128 
=log (3 x 22)8
= 8log (3 x 22)
= 8[log 3 + log22]
= 8[log 3 + 2log 2].

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Expansion of Expressions with the Help of Laws of Logarithm
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Logarithms - Exercise 10.2

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 10 Logarithms
Exercise 10.2 | Q 1.6
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