Advertisements
Advertisements
प्रश्न
F-Be-F is a liner molecule but H-O-H is angular. Explain.
उत्तर
- In the BeF2 molecule, the central beryllium atom undergoes sp hybridization giving rise to two sp hybridized orbitals placed diagonally opposite with an angle of 180°. Thus, F-Be-F is a linear molecule.
- In the H2O molecule, the central oxygen atom undergoes sp3 hybridization giving rise to four sp3 hybridized orbitals directed towards four corners of a tetrahedron. There are two lone pairs of electrons in two of the sp3 hybrid orbitals of oxygen. The lone pair-lone pair repulsion distorts the structure. Hence, H-O-H is angular or V-shaped.
APPEARS IN
संबंधित प्रश्न
In Ammonia molecule the bond angle is 107° and in water molecule it is 104°35', although in both the central atoms are sp3 hybridized Explain.
Give a reason for HF is a polar molecule
Which type of hybridization is present in the ammonia molecule?
Write the geometry and bond angle present in ammonia.
In the case of bond formation in Acetylene molecule: Name the type of Hybridization.
Define Bond Length
Predict the shape and bond angles in the following molecule:
CF4
Predict the shape and bond angles in the following molecule:
NF3
Predict the shape and bond angles in the following molecule:
HCN
Predict the shape and bond angles in the following molecule:
H2S
Using data from the Table, answer the following:
| Examples | C2H6 Ethane | C2H4 Ethene | C2H2 Ethyne |
| Structure |
\[\begin{array}{cc} \backslash \phantom{......}/\phantom{.}\\ \ce{—C – C —}\\ /\phantom{......}\backslash\phantom{.}\end{array}\] |
\[\begin{array}{cc} \backslash \phantom{......}/\\ \ce{C \text{=} C}\\ /\phantom{......}\backslash\end{array}\] |
\[\ce{- C ≡ C -}\] |
| Type of bond between carbons | single | double | triple |
| Bond length (nm) | 0.154 | 0.134 | 0.120 |
| Bond Enthalpy kJ mol-1 | 348 | 612 | 837 |
- What happens to the bond length when unsaturation increases?
- Which is the most stable compound?
- Indicate the relationship between bond strength and Bond enthalpy.
- Comment on the overall relation between Bond length, Bond Enthalpy, and Bond strength and stability.
Write the formula to calculate the bond order of molecule.
Energy required to dissociate 6 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25°C. Bond energy of H-H bond will be ____________.
What is the value of C-O-H bond angle in CH3_OH?
Which of following bonds has maximum bond length?
The hybridization and bond angle in BeCl2 molecule are ____________ respectively.
Consider the reactions.
\[\ce{C_{(s)} + 2H2_{(g)} -> CH4_{(g)}}\], ΔH = −x kcal
\[\ce{C_{(g)} + 4H_{(g)} -> CH4_{(g)}}\], ΔH = −x1 kcal
\[\ce{CH4_{(g)} -> CH3_{(g)} + H_{(g)}}\], ΔH = +y kcal
The average C-H bond enthalpy is:
Which of the following pairs have identical bond order?
The bond angle is minimum in ____________.
Identify the CORRECT option.
Which of the following is INCORRECTLY matched?
What is the bond order of B2 molecule?
Consider the ions/molecule:
\[\ce{O^+_2, O_2, O^-_2, O^{2-}_2}\]
For increasing bond order the correct option is:
What is the bona order of O2 molecules?
