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प्रश्न
factorise: 1 − (2x + 3y) − 6(2x + 3y)2
योग
उत्तर
1 − (2x + 3y) − 6(2x + 3y)2
Let (2x + 3y) = a
∴ (2x + 3y)2 = a2
∴ 1 − (2x + 3y) − 6(2x + 3y)2
= 1 − a − 6a2
= 1 − 3a + 2a − 6a2
= 1(1 − 3a) + 2a (1 − 3a)
= (1 − 3a) (1 + 2a)
= [1 − 3 (2x + 3y)] [1 + 2(2x + 3y)]
(Substituting the value of a)
= (1 − 6x − 9y) (1 + 4x + 6y)
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