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प्रश्न
Factorise : 3a2 - 1 - 2a
योग
उत्तर
3a2 - 1 - 2a
= 3a2 - 2a - 1
= 3a2 - 3a + a - 1
= 3a( a - 1 ) + 1( a - 1 )
= ( 3a + 1 )( a - 1 )
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