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Factorise : 1 - 2a - 2b - 3 (a + b)2 - Mathematics

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प्रश्न

Factorise : 1 - 2a - 2b - 3 (a + b)2

योग

उत्तर

1 - 2a - 2b - 3 (a + b)2

1 - 2(a + b) - 3(a + b)2 

Let a + b = x

= 1 - 2x - 3x2

= -3x2 - 2x + 1

= - [3x2 + 2x - 1]

= - [3x2 + (3 - 1)x - 1]

= - [3x2 + 3x - 1x - 1]

= - [3x + (x + 1) - 1(x + 1]

= - (x + 1) (3x - 1)

= (x + 1) (1 - 3x)

= (a + b + 1) [1 - 3(a + b)]

= (a + b + 1) (1 - 3a - 3b)

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अध्याय 5: Factorisation - Exercise 5 (B) [पृष्ठ ७१]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 5 Factorisation
Exercise 5 (B) | Q 11 | पृष्ठ ७१
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