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प्रश्न
Factorise:
(2a + b)2 - 6a - 3b - 4
उत्तर
(2a + b)2 - 6a - 3b - 4
= (2a + b)2 - 3(2a + b) - 4
Assume that, 2a + b = x
Therefore,
(2a + b)2 - 6a - 3b - 4
= x2 - 3x - 4
= x2 - 4x + x - 4
= 1(x - 4) + x(x - 4)
= (x + 1)(x - 4)
= (2a + b + 1)(2a + b - 4)
[resubstitute the value of x]
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