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Factorise the Following: 12 - (Y + Y2)(8 - Y - Y2) - Mathematics

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प्रश्न

Factorise the following:
12 - (y + y2)(8 - y - y2)

योग

उत्तर

12 - (y + y2)(8 - y - y2)
= 12 - a(8 - a) [Taking y + y2 = a]
= 12 - 8a + a2
= 12 - 6a - 2a + a2
= 6(2 - a) - a(2 - a)
= (2 - a)(6 - a)
= [2 - (y + y2)][6 - (y + y2)]
= (2 - y - y2)(6 - y - y2)
= (2 - 2y + y - y2)(6 - 3y + 2y - y2)
= [2(1 - y) + y(1 - y)][3(2 - y) + y(2 - y)]
= [(1 - y)(2 + y)][(2 - y)(3 + y)]
= (1 - y)(2 + y)(2 - y)(3 + y)
= (y - 1)(y + 2)(y - 2)(y + 3).

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अध्याय 5: Factorisation - Exercise 5.2

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 5 Factorisation
Exercise 5.2 | Q 3.7
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