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प्रश्न
Factorise : 3 - a (4 + 7a)
योग
उत्तर
3 - a (4 + 7a)
= 3 - 4a - 7a2
= 3 - 7a + 3a - 7a2
= 1( 3 - 7a ) + a( 3 - 7a )
= ( 3 - 7a )( a + 1 )
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