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प्रश्न
Factorise : 6a2 - 3a2b - bc2 + 2c2
योग
उत्तर
6a2 - 3a2b - bc2 + 2c2
= 6a2 - 3a2b + 2c2 - bc2
= 3a2 (2 - b) + c2 (2 - b)
= (2 - b) (3a2 + c2)
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Factorisation by Grouping
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