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Factorise : 6a2 - 3a2b - Bc2 + 2c2 - Mathematics

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Question

Factorise : 6a2 - 3a2b - bc2 + 2c2  

Sum

Solution

6a2 - 3a2b - bc2 + 2c

= 6a2 - 3a2b + 2c2 - bc2

= 3a2 (2 - b) + c2 (2 - b) 

= (2 - b) (3a2 + c2

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Factorisation by Grouping
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Chapter 13: Factorisation - Exercise 13 (B) [Page 158]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 13 Factorisation
Exercise 13 (B) | Q 9 | Page 158
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