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Question
Factorise the following by grouping the terms:
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
Sum
Solution
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
= `("p"^2 + 1/"p"^2 - 2) - (5"p" - 5/"p")`
= `(("p")^2 + (1/"p")^2 - 2 xx "p" xx 1/"p") - (5"p" - 5/"p")`
= `("p" - 1/"p")^2 - 5("p" - 1/"p")`
= `("p" - 1/"p")("p" - 1/"p" - 5)`.
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Factorisation by Grouping
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