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Question
Factorise using the grouping method :
m (x - 3y)2 + n (3y - x) + 5x - 15y
Sum
Solution
m (x - 3y)2 + n (3y - x) + 5x - 15y
= m (x - 3y)2 - n (x - 3y) + 5(x - 3y)
[Taking (x - 3y) common from all the three terms]
= (x - 3y) [m(x - 3y) - n + 5]
= (x - 3y)(mx - 3my - n + 5)
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Factorisation by Grouping
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