Factorise : 2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c - Mathematics

Factorise : 2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

Sum

2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

= 2a (b²c - 1) + 3b (b²c - 1) - 4c (b²c - 1)

= (b²c - 1) (2a + 3b - 4c)

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Factorisation by Grouping

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Chapter 13: Factorisation - Exercise 13 (B) [Page 158]

Chapter 13 Factorisation
Exercise 13 (B) | Q 20 | Page 158

Factorise by the grouping method : a²x² + (ax² + 1) x + a

Factorise by the grouping method : y² - (a + b) y + ab

factorise: 2a² - 17ab + 26b²

factorise: 5 + 7x - 6x²

factorise: x(3x + 14) + 8

Factorise the following by grouping the terms:
15xy - 9x - 25y + 15

Factorise the following by grouping the terms:
8(2a + b)² - 8a -4b

Factorise the following by grouping the terms:
9x³ + 6x²y² - 4y³ - 6xy

Factorise the following by grouping the terms:
3ax² - 5bx² + 9az² + 6ay² - 10by² - 15bz²

Factorise the following by grouping the terms:
p²x² + (px² + 1)x + p