Advertisements
Advertisements
Question
Factorise : ax + 2bx + 3cx - 3a - 6b - 9c
Sum
Solution
ax + 2bx + 3cx - 3a - 6b - 9c
= x (a + 2b + 3c) - 3 (a + 2b + 3c)
= (a + 2b + 3c) (x - 3)
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise by the grouping method : (2a-b)2 -10a + 5b
Factorise using the grouping method :
a2 + 4b2 - 3a + 6b - 4ab
Factorise : a2 + ax + ab + bx
factorise: a2 + 5a + 6
factorise: (x - 2y)2 - 12(x - 2y) + 32
factorise: x2y2 - 3xy - 40
factorise: (3x - 2y)2 - 5(3x - 2y) - 24
Factorise the following by grouping the terms:
15xy - 9x - 25y + 15
Factorise the following by grouping the terms:
x2 - (p + q)x + pq
Factorise the following by grouping the terms:
2p(a2 - 2b2) -14p + (a2 - 2b2)2 - 7(a2 - 2b2)
