Advertisements
Advertisements
प्रश्न
Factorise : ax + 2bx + 3cx - 3a - 6b - 9c
बेरीज
उत्तर
ax + 2bx + 3cx - 3a - 6b - 9c
= x (a + 2b + 3c) - 3 (a + 2b + 3c)
= (a + 2b + 3c) (x - 3)
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method: 16 (a + b)2 - 4a - 4b
Factorise by the grouping method : (ax + by)2 + (bx - ay)2
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
Factorize using the grouping method:
x2 + y2 + x + y + 2xy
factorise: 2x2 + xy - 6y2
factorise: 8 + 6(a + b) - 5(a + b)2
Factorise: 2(x + 2y)2 − 5(x + 2y) + 2
factorise: (3x - 2y)2 - 5(3x - 2y) - 24
Factorise the following by grouping the terms:
8(2a + b)2 - 8a -4b
Factorise the following by grouping the terms:
p2x2 + (px2 + 1)x + p