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प्रश्न
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
बेरीज
उत्तर
`a^2 + 1/a^2 - 2 - 3a + 3/a`
= `( a - 1/a )^2 - 3( a - 1/a )`
= `( a - 1/a )[( a - 1/a ) - 3]`
= `( a - 1/a )[ a - 1/a - 3]`
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Factorisation by Grouping
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