Advertisements
Advertisements
प्रश्न
Factorise by the grouping method : a4 - 2a3 - 4a + 8
योग
उत्तर
a4 - 2a3 - 4a + 8 = a3( a - 2 ) - 4( a - 2 )
= ( a3 - 4 )( a - 2 )
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise using the grouping method :
a2 + 4b2 - 3a + 6b - 4ab
Factorise : ab - 2b + a2 - 2a
Factorise : a3 - a2 - ab + a + b - 1
factorise: 4c2 + 3c - 10
factorise: 1 - 18x - 63x2
factorise: x(3x + 14) + 8
factorise: 5 - 4x(1 + 3x)
factorise: 3a2x - bx + 3a2 - b
Factorise the following by grouping the terms:
4abx2 + 49aby2 + 14xy(a2 + b2)
Factorise the following by grouping the terms:
x2 - (p + q)x + pq