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प्रश्न
Factorise the following by grouping the terms:
4abx2 + 49aby2 + 14xy(a2 + b2)
योग
उत्तर
4abx2 + 49aby2 + 14xy(a2 + b2)
= 4abx2 + 49aby2 + 14a2xy + 14b2xy
= (4abx2 + 14a2xy) + (14b2xy + 49aby2)
= 2ax(2bx + 7ay) + 7by(2bx + 7ay)
= (2bx + 7ay)(2ax + 7by).
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Factorisation by Grouping
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