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प्रश्न
Factorise the following by grouping the terms:
9x3 + 6x2y2 - 4y3 - 6xy
योग
उत्तर
9x3 + 6x2y2 - 4y3 - 6xy|
= 9x3 + 6x2y2 - 6xy - 4y3
= (9x3 + 6x2y2) - (6xy + 4y3)
= 3x2(3x + 2y2) - 2y(3x + 2y2)
= (3x + 2y2)(3x2 - 2y).
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Factorisation by Grouping
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