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प्रश्न
Factorise completely: x2 + 6xy + 9y2 + x + 3y
योग
उत्तर
x2 + 6xy + 9y2 + x + 3y
= [(x)2 + 2 × x × 3y + (3y)2] + (x + 3y)
= [x + 3y]2 + (x + 3y)
= (x + 3y) (x + 3y) + (x + 3y)
= (x + 3y) (x + 3y + 1)
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Factorising Completely
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