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प्रश्न
Factorise completely: 4a2 -12ab + 9b2 + 4a- 6b
योग
उत्तर
4a2 -12ab + 9b2 + 4a- 6b
= [(2a)2 - 2 × 2a × 3b + (3b)2] + 2(2a - 3b)
= (2a - 3b)2 + 2(2a - 3b)
= (2a - 3b)(2a - 3b + 2)
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Factorising Completely
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