Advertisements
Advertisements
Question
Factorise completely: 4a2 -12ab + 9b2 + 4a- 6b
Sum
Solution
4a2 -12ab + 9b2 + 4a- 6b
= [(2a)2 - 2 × 2a × 3b + (3b)2] + 2(2a - 3b)
= (2a - 3b)2 + 2(2a - 3b)
= (2a - 3b)(2a - 3b + 2)
shaalaa.com
Factorising Completely
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise completely: 8x2y - 18y3
Factorise completely: ax2 - ay2
Factorise completely: 625 - x4
Factorise completely: x2 - y2 - 2x + 2y
Factorise completely: 3x2 + 15x - 72
Factorise completely: 2a2 - 8a - 64
Factorise completely: 5b2 + 45b + 90
Factorise completely: 3x2y + 11xy + 6y
Factorise completely: a2 + 2ab + b2 - c2
Factorise completely: x2 + 6xy + 9y2 + x + 3y
